1.

Select the incorrect statements for the equillibrium under standard condition: `H_(2)O_((s))hArrH_(2)O_((l)), DeltaS_(1)^(@)` `H_(2)O_((l))hArrH_(2)O_((v)), DeltaS_(2)^(@)` `H_(2)O_((s))hArrH_(2)O_((v)), DeltaS_(3)^(@)`A. `Delta S_(1)^(@) gt Delta S_(2)^(@)`B. `Delta S_(2)^(@) gt gt gt Delta S_(1)^(@)`C. `DeltaS_(3)^(@) gt Delta S_(2)^(@)`D. `Delta S_(3)^(@) gt Delta S_(1)^(@)`

Answer» Correct Answer - B::C::D
`H_(2)O_((s))` has more ordered arrangement. Also
`Delta S_(2)^(@) = S_(H_(2)O_((v)))^(@) - S_(H_(2)O_((l)))^(2), Delta S_(0)^(1) = S_(H_(2)O_((l)))^(@)-S_(H_(2)O_((s)))^(@)`
`:. S_(H_(2)O_((v)))^(@)` is maximum and thus `Delta S_(2)^(@) gt gt gt Delta S_(1)^(@)`


Discussion

No Comment Found

Related InterviewSolutions