Semiconductor Ge has forbidden gap of 1.43 eV. Calculate maximum wavelength which result from electron hole combination.

Semiconductor Ge has forbidden gap of 1.43 eV. Calculate maximum wavel

1.	Semiconductor Ge has forbidden gap of 1.43 eV. Calculate maximum wavelength which result from electron hole combination.
Answer» Correct Answer - 8654 Å Energy `E_(min)=(hc)/(lamda_(max))` `becauselamda_(max)=(hc)/(E_(min))` `=(6.6xx10^(-34)xx3xx10^(8))/(1.43xx1.6xx10^(-19))m` `=8.654xx10^(-7)m` `=8654xx10^(-10)m` `=8654Å`

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Semiconductor Ge has forbidden gap of 1.43 eV. Calculate maximum wavelength which result from electron hole combination.

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