Shatabdi express starts from rest and attains a velocity of 108km/h in

1.	Shatabdi express starts from rest and attains a velocity of 108km/h in 2min . If acceleration is uniform fild acceleration and displacement of the train..
Answer» Answer : ACCELERATION of the train is 0.25m/s² Displacement of the train is 1.8km Explanation : According to the QUESTION It is GIVEN that , Initial velocity ,u = 0m/s Final velocity ,v = 108×5/18 = 30m/s Time taken ,t = 2min = 260 = 120s we have to calculate the uniform acceleration of the train and displacement of the train . Firstly we calculate the uniform acceleration of the train . Using Kinematics Equation a = v-u/t Substitute the value we get ➾ a = 30-0/120 ➾ a = 30/120 ➾ a = 1/4 ➾ a = 0.25m/s² Hence, the* acceleration of the train is 0.25m/s² Now, calculating the displacement of the train . Again using Kinematics Equation v² = u² + 2as Puttng all the values we get ➾ 30² = 0² + 2×0.25 × s ➾ 900 = 0 + 0.50 × s ➾ 900 = 0.50×s ➾ s = 900/0.50 ➾ s = 1800m ➾ s = 1.8km Hence, the displacement of the train is 1.8 kilometres.

Shatabdi express starts from rest and attains a velocity of 108km/h in 2min . If acceleration is uniform fild acceleration and displacement of the train..

Answer»

Answer :

ACCELERATION of the train is 0.25m/s²

Displacement of the train is 1.8km

Explanation :

According to the QUESTION

It is GIVEN that ,

we have to calculate the uniform acceleration of the train and displacement of the train .

Firstly we calculate the uniform acceleration of the train .

Using Kinematics Equation

Substitute the value we get

➾ a = 30-0/120

➾ a = 30/120

➾ a = 1/4

➾ a = 0.25m/s²

Now, calculating the displacement of the train .

Again using Kinematics Equation

Puttng all the values we get

➾ 30² = 0² + 2×0.25 × s

➾ 900 = 0 + 0.50 × s

➾ 900 = 0.50×s

➾ s = 900/0.50

➾ s = 1800m

➾ s = 1.8km