InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Show how you would connect three resistors, each of resistance 6Omega so that combination has a resistance of (i) 9Omega (ii) 4Omega |
|
Answer» Solution :i] For getting a resistance of `9Omega`, the two resistors should be connected in parallel and ONE in series with them. The equivalent resistance of the two resistors in parallel, `R_(p)` is GIVEN by `1/R_(p)=1/6+1/6=2/6toR_(p)=3Omega` Now, the equivalent resistance of `R_(P)and6Omega` in series is given by DIAGRAM. `R=R_(p)+6=3+6=9Omega`.  ii] To GET a resistance of `4Omega`, two resistors should be connected in series and one in parallel to them. The equivalent resistance of the two resistors in series is given by `R_(p)=6Omega+6Omega=12Omega` Now, the equivalent resistance of `R_(p)and6Omega` in parallel is given by diagram. `1/R=1/R_(p)+1/6=2/6+1/6=(1+2)/12=3/12=1/4` `R=4Omega` 
|
|