1.

Show that 1/2 gt2 has same dimension of distance

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Answer:

Since g is acceleration DUE to GRAVITY, then its dimensions are the same as that of acceleration. therefore,[g]= [LT^-2].

Now, dimension of 1/2[gt^2]=[L]

We can write constant as it is DIMENSIONLESS.

[gt^2]=[L]

⇒ [g][t^2]=[L]

⇒ [g]=[L]/[t^2]

⇒ [g]=[L]/([T]^2)

⇒ [g]=[LT^-2]

[Writing conventions may differ.]

Hence, Dimension of g = M°LT^(-2) or L/T²



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