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Show that 1/2 gt2 has same dimension of distance |
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Answer» Answer: Since g is acceleration DUE to GRAVITY, then its dimensions are the same as that of acceleration. therefore,[g]= [LT^-2]. Now, dimension of 1/2[gt^2]=[L] We can write constant as it is DIMENSIONLESS. [gt^2]=[L] ⇒ [g][t^2]=[L] ⇒ [g]=[L]/[t^2] ⇒ [g]=[L]/([T]^2) ⇒ [g]=[LT^-2] [Writing conventions may differ.] Hence, Dimension of g = M°LT^(-2) or L/T² |
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