1.

Show that the line `x/a+y/b=1`touches the curve `y=b e^(-x/a)`at the point where it crosses the y-axis.

Answer» `y= be^(-x/a)`
`dy/dx = be^(-x/a) (-1/a) `
`dy/dx = -b/a e^(-x/a)`
now, `x/a + y/b = 1`
`ax + ay - ab = 0`
slope=`-b/a`
now, `-b/ae^(-x/a) = -b/a`
`e^(x/a) = 1`
`x=0`
`y=b`
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