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Show that the line `x/a+y/b=1`touches the curve `y=b e^(-x/a)`at the point where it crosses the y-axis. |
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Answer» `y= be^(-x/a)` `dy/dx = be^(-x/a) (-1/a) ` `dy/dx = -b/a e^(-x/a)` now, `x/a + y/b = 1` `ax + ay - ab = 0` slope=`-b/a` now, `-b/ae^(-x/a) = -b/a` `e^(x/a) = 1` `x=0` `y=b` Answer |
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