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Show that the points (-2, 5), (3, -4) and (7, 10) are the vertices of a right triangle. |
Answer» Let the three points be A(-2, 5), B(3, - 4) and C(7, 10). Then AB2 = (3 + 2)2 + (-4 - 5)2 = 106 BC2 = (7 - 3)2 + (10 + 4)2 = 212 AC2 = (7 + 2)2 + (10 - 5)2 = 106 We see that BC2 = AB21 + AC2 212 = 106 + 106 212 = 212 ∠A = 900 Thus, ABC is a right triangle, right angled at A. |
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