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Show that the sequence defined by an = 5n – 7 is an A.P., find its common difference. |
Answer» Given, an = 5n – 7 Now putting n = 1, 2, 3, 4 we get, a1 = 5(1) – 7 = 5 – 7 = -2 a2 = 5(2) – 7 = 10 – 7 = 3 a3 = 5(3) – 7 = 15 – 7 = 8 a4 = 5(4) – 7 = 20 – 7 = 13 We can see that, a2 – a1 = 3 – (-2) = 5 a3 – a2 = 8 – (3) = 5 a4 – a3 = 13 – (8) = 5 Since the difference between the terms is common, we can conclude that the given sequence defined by an = 5n – 7 is an A.P with common difference 5. |
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