1.

Show that the sequence defined by an = 5n – 7 is an A.P., find its common difference.

Answer»

Given, an = 5n – 7

Now putting n = 1, 2, 3, 4 we get,

a1 = 5(1) – 7 = 5 – 7 = -2

a2 = 5(2) – 7 = 10 – 7 = 3

a3 = 5(3) – 7 = 15 – 7 = 8

a4 = 5(4) – 7 = 20 – 7 = 13

We can see that,

a2 – a= 3 – (-2) = 5

a3 – a= 8 – (3) = 5

a4 – a= 13 – (8) = 5

Since the difference between the terms is common, we can conclude that the given sequence defined by an = 5n – 7 is an A.P with common difference 5.



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