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सिद्ध कीजिए कि - `((2n+1)!)/(n!) = 2^(n)[1.3.5"…."(2n-1).(2n+1)]`

Answer» बायाँ पक्ष `= ((2n+1)!)/(n!)`
`= (1.2.3"….."(2n-2)(2n-1)2n(2n+1))/(n!)`
`= ([(1.3.5)"…."(2n-1)(2n+1)].[(2.4.6.8)"…"(2n-2)(2n)])/(n!)`
`= 2^(n) [1.3.5"…."(2n-1)(2n+1)] =` दायाँ पक्ष


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