1.

सिद्ध कीजिए कि `((2n)!)/(n!) = {1.3.5"….."(2n-1)}2^(n)`

Answer» बायाँ पक्ष `= ((2n)!)/(n!) = (1.2.3.4"......"(2n-2)(2n-1)2n)/(n!)`
`= ([1.3.5"….."(2n-1)][2.4.6"….."(2n-2)(2n)])/(n!)`
`= ([1.3.5.7"….."(2n-1)]2^(n).[1.2.3"…"(n-1).n])/(n!)`
` ([1.3.5.7"….."(2n-1)]2^(n) . n!)/(n!)`
`= [1.3.5.7"..."(2n-1)]2^(n) =` दायाँ पक्ष


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