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सिद्ध कीजिए कि `(tan theta+sin theta)/(tan theta-sin theta)=(sec theta+1)/(sec theta-1)` |
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Answer» यहाँ `L.H.S. =(tan theta+sin theta)/(tan theta-sin theta)` `((sin theta)/(cos theta)+sintheta)/((sin theta)/(cos theta)-sin theta)=(sin theta((1)/(costheta)+1))/(sin theta((1)/(cos theta)-1))=((1)/(cos theta)+1)/((1)/(cos theta)-1)=(sec theta+1)/(sec theta-1)=R.H.S.` |
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