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    				| 1. | सिद्ध कीजिए: (xa-b)a-b. (xb-c)b+c .(xc-a)c+a = 1 | 
| Answer» L.H.S. = x(a-b)(a+b) + (b-c)(b+c) + (c-a)(c+a) = \(x^{a^2-b^2+b^2-c^2+c^2-a^2}\) = x0 = 1 = R.H.S. | |