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Simplify (1 – cos θ) (1 + cos θ) (1 + cot2 θ) |
Answer» Given that (1 – cos θ) (1 + cos θ) (1 + cot2 θ) = (1 – cos2 θ) (1 + cot2 θ) [∵ (a – b) (a + b) = a2 – b2] = sin2 θ. cosec2 θ [∵ 1 – cos2 θ = sin2 θ; 1 + cot2 θ = cosec2 θ] = sin2 θ . \(\frac{1}{sin^2\, θ}\) [∵ cosec θ = \(\frac{1}{sin\, θ}\) ] = 1 |
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