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Simplify: `(sin 8theta cos theta - sin 6theta cos 3theta)/(cos 2theta cos theta - sin 3theta sin4theta)` |
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Answer» `(1/2[sin9theta+sin7theta-sin9theta-sin3theta])/(1/2[cos3theta+costheta-costheta+cos7theta])` `(sin7theta-sin3theta)/(cos3theta+cos7theta)` `(2cos5thetasin2theta)/(2cos5thetacos2theta)` `tantheta`. |
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