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Simplify the expression: XY’ + X’ + Y’X’.(a) X’ + Y(b) XY’(c) (XY)’(d) Y’ + XThe question was posed to me by my school teacher while I was bunking the class.I would like to ask this question from Minimization of Boolean Functions topic in portion Boolean Algebra and Modeling Computations of Discrete Mathematics

Answer»

The correct answer is (c) (XY)’

Easy explanation: GIVEN XY’+X’+Y’X’ = Y’(X+X’) + X’ = Y’.1 + X’ = X’ + Y’ = (XY)’ [De Morgan’s law].



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