InterviewSolution
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InterviewSolution
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`sin(1/4sin^(- 1)(sqrt 63/8)i s`A. `(1)/(2)`B. `(1)/(3)`C. `(1)/(2sqrt(2))`D. `(1)/(5)` |
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Answer» Correct Answer - C We have sin `((1)/(4)"sin"^(-1)(sqrt(63))/(8))` Let `"sin"^(-1)(sqrt(63))/(8)=theta` `therefore (sqrt(63))/(8)=sin theta` `rArr cos. theta = (1)/(8)` `therefore cos.(theta)/(2)=sqrt((1+cos theta)/(2))=sqrt((1+(1)/(8))/(2))=(3)/(4)` `rArr = sin.(theta)/(4)=sqrt((1-cos.(theta)/(2))/(2))=sqrt((1-(3)/(4))/(2))=(1)/(2sqrt(2))` |
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