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`sin^(-1) (5/x) +sin^(-1) (12/x) =pi/2` |
Answer» `sin^(-1)(5/x)=pi/2-sin^(-1)(12/x)` `pi/2-cos^(-1)(5/x)=pi/2-sin^(-1)(12/x)` `cos^(-1)(5/x)=sin^(-1)(12/x)=theta` `costheta=5/x,sintheta=12/x` `sin^2theta+cos^2theta=1` `144/x^2+25/x^2=1` `169/x^2=1` `x=pm13` possible value is +13. |
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