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Sin - 2sin ^3 / 2cos^2 - cos = tan

Answer» TION:ANSWERBy solving LHS we get⇒cosA(2cos2A−1)sinA(1−2sin2A)=TANA(cos2Acos2A) [∵1−2sin2A=cos2A2cos2A−1=cos2A]=tanA=RHSHence PROVED.


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