1.

`sin theta + cos theta =sqrt(2), ` then `sin^(16)theta `=______A. `(cos^(16)theta )/(2^(16))`B. `(sec^(16)theta)/(2^(8))`C. `(1)/(2 sec^(16) theta )`D. `(1)/(2^(16) cos^(16) theta )`

Answer» Correct Answer - D
` sin theta+ cos theta=sqrt(2)`
`sin^(2)theta+ cos^(2) theta +2 sin theta cos theta =2`
`implies 2 sin theta cos theta =1`
` sin theta cos theta=(1)/(2)`
`sin^(16)=(1)/(2^(16)cos^(16)theta)`.


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