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`sin theta + cos theta =sqrt(2), ` then `sin^(16)theta `=______A. `(cos^(16)theta )/(2^(16))`B. `(sec^(16)theta)/(2^(8))`C. `(1)/(2 sec^(16) theta )`D. `(1)/(2^(16) cos^(16) theta )` |
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Answer» Correct Answer - D ` sin theta+ cos theta=sqrt(2)` `sin^(2)theta+ cos^(2) theta +2 sin theta cos theta =2` `implies 2 sin theta cos theta =1` ` sin theta cos theta=(1)/(2)` `sin^(16)=(1)/(2^(16)cos^(16)theta)`. |
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