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sin4 θ + 2 cos2 θ \(\bigg(1-\frac{1}{sec^2\,\theta}\bigg)\) + cos4 θ =(a) 1 (b) 2 (c) √2 (d) 0 |
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Answer» (a) 1 sin4 θ + 2 cos2 θ \(\bigg(1-\frac{1}{sec^2\,\theta}\bigg)\) + cos4 θ = sin4 θ + 2cos2 θ (1 cos2 θ) + cos4 θ = sin4 θ + 2cos2 θ. sin2 θ + cos4 θ = (sin2 θ + cos2 θ)2 = 12 = 1 |
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