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Six charges each equal to +Q are placed at corners of regular hexagon of side (l) the electric potential and electric field at point p where diagonals intersect are |
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Answer» Explanation: The electric potential at the INTERSECTION of the DIAGONALS PP is the SUM of the electric potentials from all the POINT charges. As a regular hexagon is composed of EQUILATERAL triangles all these point charges have the distance xx from the point PP. VE(P)=14πϵ0(6Qx)=3Q2πϵ0xVE(P)=14πϵ0(6Qx)=3Q2πϵ0x. |
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