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Six identical particles each of mass `m` are arranged at the corners of a regular hexagon of side length `L`. If the mass of one of the particle is doubled, the shift in the centre of mass isA. `L`B. `6L//7`C. `L//7`D. `L/(sqrt(3))` |
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Answer» Correct Answer - C shift `=(md)/(M+m)` |
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