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Six identical particles each of mass `m` are arranged at the corners of a regular hexagon of side length `L`. If the mass of one of the particle is doubled, the shift in the centre of mass isA. `L/8`B. `(sqrt(3)L)/8`C. `(3L)/16`D. `(3L)/4` |
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Answer» Correct Answer - B `shift=(md)/(M+m)` |
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