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Six wires of current l 1-1A, l2-2A, 13 ЗА 14-1 A 15-5A and 16-4A cut the page perpendicularly at the points1, 2, 3, 4, 5 and 6 respectively as shown in the figure. Find the value of the integral фв.dl around the closed path.284 |
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Answer» {b.dl = μI where I is the sum of current enclosed by the loop in positive direction , say upward(•) since I5 is not in the loop , we will neglect it.so total positive I = I1+I2+I3-I4-I6 = 1+2+3-1-4 = 6-5 = 1A therefore {b.dl = μI |
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