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Solution of equation x2 + x – 2 = 0 in Roster form is: (A) {1, 2}(B) {-1, 2} (C) {-1, -2} (D) {1, -2}

Answer»

Answer is (D)

Given, x2 + x – 2 = 0 

x2 + 2x – x – 2 = 0 

x(x + 2) – 1(x + 2) = 0 

(x + 2)(x – 1) = 0 

when x + 2 = 0 then x = -2 

when x – 1 = 0 then x = 1 

Hence, roster form of equation is {-2, 1} or {1, -2}



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