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Solution of the differential equation 2y sinx.dy/dx = 2 sin x cos x – y2 cos x satisfying y(π/2) = 1 is(a) y2 = sin x (b) y = sin2 x (c) y2 = cos x +1 (d) None of these |
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Answer» Correct option (a) y2 = sin x Explanation: (2ydy/dx) sinx + y2 cosx = sin 2x d/dx(y2 sinx) = sin 2x Integrating both sides, y2 sin x = -1/2 soc2x + C Now yπ/2 = 1 1.sinπ/2 = -1/2.(-1) + C C = 1/2 y2 sin x = 1/2(1 - cos 2x) y2 sin x = 1/2.2 sin2x y2 = sin x |
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