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Solve: (1 – x) dy – (1 + y) dx = 0 |
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Answer» (1 – x) dy – (1 + y) dx = 0 Separating the variables, (1 – x)dy = (1 + y) dx dy/(1 + y) = dx/(1 - x) Integrating, we get ∫1/(1 + y)dy = ∫1/(1 - x)dx log(y + 1) = -log(1 – x) + log c log(y + 1) + log(1 – x) = log c (y + 1) (1 – x) = c |
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