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Solve 3 – 2x < 9, when x ∈ R. Express the solution in the form of interval. |
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Answer» We have, 3 – 2x < 9, Transposing 3 to RHS, − 2x < 9 – 3 Or − 2x < 6 Or \(\frac{-2x}{-2}\) > \(\frac{6}{-2}\) Or x >−3 ∴ When x is real, the solution is (- 3, ∞) |
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