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Solve, −3 ≤ −3x + 2 < 4, x ∈ R. |
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Answer» We have, −3 ≤ −3x + 2 <4, ⇒ −3 − 2 ≤ −3x + 2 − 2 < 4 − 2 (Adding -2 in inequality) ⇒ −5 ≤ −3x < 2 ⇒ \(\frac{-5}{-3}\) ≥ \(\frac{-3x}{-3}\) >\(\frac{2}{-3}\) (Dividing by −3) Or ⇒ \(-\frac{2}{3}\) > x ≤ \(-\frac{5}{3}\) Or x ∈\(-\frac{2}{3}\),\(-\frac{5}{3}\) |
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