InterviewSolution
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InterviewSolution
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Solve : `3x^(2) + 8ix + 3 = 0`. |
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Answer» The given equation is `3x^(2)+8ix+3=0`. This is of the form `ax^(2)+bx+c=0`, where a = 3, b = 8i and c = 3. `therefore" "(b^(2)-4ac)={(8i)^(2)-4 xx 3 xx 3}=(-64-36)=-100 lt 0`. So, the given equation has complex roots. These roots are given by `(-b+- sqrt(b^(2)-4ac))/(2a)=(-8i+- sqrt(-100))/(2 xx 3)" "[because b^(2)-4ac=-100]` `=(-8i+-10i)/(6)=(-4i+-5i)/(3)`. Thus, the roots of the given equation are `(-4i+5i)/(3)=(i)/(3)and(-4i+5i)/(3)=(-9i)/(3)=-3i`. `therefore" ""solution set"={(i)/(3),-3i}`. |
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