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Solve `4^x+6^x=9^xdot` |
Answer» Correct Answer - `x = log_(2//3)((sqrt(5)-1)/(2))` `4^(x) + 6^(x) = 9^(x)` or `((4)/(9))^(x)+((2)/(3))^(x) = 1` Putting `((2)/(3))^(x) = y ,` we have `y^(2) + y - 1 = 0` or ` y = (-1pmsqrt(5))/(2)` `rArr ((2)/(3))^(x) = (sqrt(5-1))/(2) (because((2)/(3))^(x) gt0)` `rArr x = log_(2//3)((sqrt(5-1))/(2)) ` |
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