Hello all,

PLEASE will someone show me how to write a batch file that will delete any space before the last \ in a var.

eg turn "\Rock and Roll\Music \Dance" into "\Rock and Roll\Music\Dance"

The length and CONTENTS of the string are unknown  but the space is always immediately before the last \

Many Thanks!

Chrisyou can use vbscript instead
Code: [SELECT]strData = "\Rock and Roll\Music \Dance"
ArrayData = Split(strData,"\")
For i=LBound(ArrayData) To UBound(ArrayData)
ArrayData(i) = Trim(ArrayData(i))
Next
strFinal = Join(ArrayData,"\")
WScript.Echo strFinal

'or another way, using replace
WScript.Echo Replace(strData," \","\")


echo off
set string1=\Rock and Roll\Music \Dance
set string2=%string1: \=\%
echo %string1%
echo %string2%
Thanks Salmon Trout! It worked perfectly!To replace every occurence of abc with xyz in a string:

Change the string itself:

Code: [Select]set string=%string:abc=xyz%
Or create a new, CHANGED string:

Code: [Select]set string2=%string1:abc=xyz%
Usual remarks about delayed expansion etc apply

Quote from: Salmon Trout on July 26, 2009, 03:06:01 AM

echo off
set string1=\Rock and Roll\Music \Dance
set string2=%string1: \=\%
echo %string1%
echo %string2%

I think OP will not ever have such situations, but just for resiliency and completeness, i am sure the above can be made to remove more than 1 space eg

Code: [Select]\Rock and Roll\Music     \Dance