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Solve : Classic ASP: error '800a000d' Type mismatch? |
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Answer» Hello Microsoft VBScript runtime error '800a000d' 'maria' refers to my chosen password. Line 23 is this: if username = "" or password or fullname or strEmail = "" then strEmail corresponds to the email column in my MS Access 2003 database. The rest of my CODE looks like this: Code: [Select]<% username = "" password = "" ErrorMessage = "" strEmail = "" fullname = "" if request.form <> "" then username = Request.Form("username") password = Request.Form("password") fullname = Request.Form("fullname") strEmail = Request.Form("strEmail") if username = "" or password or fullname or strEmail = "" then [color=red]<---- where the error occurs[/color] ErrorMessage = "You must specify a username, password, your full name and email address." else set conn = Server.CreateObject("ADODB.Connection") conn.Provider = "Microsoft.Jet.OLEDB.4.0" conn.Open("E:\myDatabase.mdb") set rs = Server.CreateObject("ADODB.recordset") rs.Open "Select * FROM Users WHERE strEmail = '" & username & "'" & fullname & "'", conn if rs.EOF = false then if rs.fields("password") = password then Response.Redirect("Default.asp") end if end if ErrorMessage = "Login failed" end if end if if ErrorMessage <> "" then response.write("<p>" & ErrorMessage & "</p>") response.write("<p>Please correct the errors and TRY again.</p>") end if %> <h1>Login</h1> <form method="post" action=""> <fieldset> <legend>Log In to Your Account</legend> <ol> <li> <label>Username:</label> <input type="text" id="username" name="username" /> </li> <li> <label>Password:</label> <input type="password" id="password" name="password" /> </li> <li> <label>Full name:</label> <input type="text" id="fullname" name="fullname" /> </li> <li> <label>Email:</label> <input type="text" id="strEmail" name="strEmail" /> </li> <li> <p><input type="submit" value="Login" /></p> </li> </ol> </fieldset> </form> </div> </body> </html> What am I doing wrong, please? High1Quote Code: [Select] if username = "" or password or fullname or strEmail = "" then Or cannot be used on two strings. You are missing ="" COMPARISONS for password and fullname.Hello mastermind Many thanks for your reply. So I would have to use if username = "" or password = "" then only? How would I include 'fullname' and 'strEmail', if I may ask? Thank you High1I'll try using this (and abandon fullname as it's not really essential): if username = "" or password = "" or strEmail = "" then High1 |
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