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Solve d2y/dx2 - 2k(dy/dx) + k2y = 0 differential equations. |
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Answer» Given (D2 – 2kD + k2 )y = 0, D = d/dx The auxiliary equations is m2 – 2km + k = 0 ⇒ (m – k)2 = 0 ⇒ m = k, k Roots are real and equal The complementary function (C.F) is (Ax + B) ekx The general solution is y = (Ax + B) ekx |
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