1.

Solve d2y/dx2 - 2k(dy/dx) + k2y = 0  differential equations.

Answer»

Given (D2 – 2kD + k2 )y = 0, D = d/dx

The auxiliary equations is m2 – 2km + k = 0

⇒ (m – k)2 = 0 

⇒ m = k, k 

Roots are real and equal 

The complementary function (C.F) is (Ax + B) ekx 

The general solution is y = (Ax + B) ekx



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