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Solve d2y/dx2 - 6(dy/dx) + 8y = 0 differential equations. |
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Answer» Given (D – 6D + 8) y = 0, D = d/dx The auxiliary equations is m2 – 6m + 8 = 0 (m – 4)(m – 2) = 0 m = 4, 2 Roots are real and different The complementary function (C.F) is (Ae4x + Be2x ) The general solution is y = Ae4x + Be2x |
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