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Solve for x, the inequalities in 4x + 3 ≥ 2x + 17, 3x – 5 < – 2. |
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Answer» According to the question, 4x + 3 ≥ 2x + 17 ⇒ 4x – 2x ≥ 17 – 3 ⇒ 2x ≥ 14 ⇒ x ≥ 7 …(i) Also, 3x – 5 < – 2 ⇒ 3x < 3 ⇒ x < 1 …(2) Since, equations [i] and [ii] cannot be possible simultaneously, We conclude that x has no solution. |
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