How do I display the full path of a filename when working with batch files? I've been working on this for about an hour and can't figure it out.Show what you have done for your batch ATTEMPT.
@echo off

rem Batch Program to Add a Prefix to Filename in the Current
remDirectory and its Subdirectories

rem Name: (blank) Date: 9/6/07
remFilename: AddPrefixSub.bat

remThis batch program receives a prefix and a file
remspecification as replaceable parameters,
remand for each matching file in the current directory
remand its subdirectories, renames it,
remadding the word to the beginning of the filename.

remJump to error message if you did not type both
rem a word and a filespec as parameters:
if TEST%2 == test GOTO :ERR

rem Rename each matching file, adding the word:
for /r %%a in (%2) do ren "%%~a" "%1 %%~nxa"

remEnd the program:
GOTO :EOF

:ERR
remError message if you left out the prefix and filespec:
echo Please include one prefix and one filespec,
echo like this:
echo AddPrefixSub prefix filespec

I want to add a command that will show the full path of the filename. And I want to add it between the DO and the REN on the line with the For command, using an & operator after the command and before REN. I'm just not sure of the command. I've looked everywhere I can think of. Everybody on here seems to be a great help to me, so thanks in advance. It's not that easy learning how to do this kind of stuff. Quote from: marco on September 10, 2007, 02:51:14 AM

I want to add a command that will show the full path of the filename.

if test%2 == test GOTO :ERR