Ok, Hi! This is my first topic here, so I will go to the point directly:
I have this Batch FILE:
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@echo off
:checkstage
IF "%0"=="%0" goto comparch
IF "%1" == "help" goto 1
IF "%1"=="emulate" goto 2
IF %2== goto 3

:comparch
echo Comparch v1.0
echo 2015 (C) uSoft. All Rights Reserved.
cd..
call shell.bat

:1
echo Usage Description
echo ===== ===========
echo comparch help Displays help about commands
echo comparch emulate [file] Displays help about commands
cd..
call shell.bat

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That file is called by another batch file, shell.bat.
And it is like this:

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@echo off
title Comparch v1.0 Shell
:shell
cd bin
set/P cli= *

IF %cli%==comparch call comparch.bat

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So, my problem is that when I type, for example, comparch help, it displays:

help== was not expected at this time

And it leaves instantly.

What is wrong?

Pd: When I type "comparch" alone without any parameters, it runs correctly...Look at your test for %2TO clarify

This line:

IF %2== goto 3

will break the script if there is no second parameter passed to the script (if %2 is empty when the script is RUN) This is because you must have something on both sides of the == in an IF test. The usual way to beat this is to use quotes like this

IF "%2"=="" goto 3

Also,

When this line is run:

set/p cli= *

However if the user just hits ENTER so set /p captures an empty string, then this line:

IF %cli%==comparch call comparch.bat

will break the script because %cli% will be empty so do this:

IF "%cli%"=="comparch" call comparch.bat

This will fail if the user types the answer using any upper case characters. I am sure you can find out how to get around this, if the boast in your sig is true.

Finally, what is this line supposed to do?

IF "%0"=="%0" goto comparch
Thank you, and... "%0==%0" It was 2 AM, I didn't even wanted to think anymoreQuote from: BatchProgrammer on October 29, 2015, 04:02:49 PM

It was 2 AM, I didn't even wanted to think anymore