I want to find the path of a file

for eg: if the file is aaa.txt
I can able to find the path as c:\test\aaa.txt
But the way I want is c:\test alone...
can anyone help me in this regardCode: [Select]@echo off
for /f %%I in ('dir "C:\aaa.txt" /s /b) do @echo %%~dpI
echo.
pauseUse the above code in a batch file.

I THINK that should work (BTW, this thread should probably be under Microsoft DOS, but...).

This batch returns the file path and drive letter only, and then pauses.


I know that it needs some work (i.e. to find the file without having to INPUT the name), but it'll get done soon.


EDIT: FIXED!thank u very much dude...

if suppose
iam having the filename in one variable like
set filename = aaa.txt and the path in one variable like
filepath = c:\test\aaa.txt

if it is in this scenario how should i get thatOh. I get you.

Code: [Select]@echo off
for %%I in (C:\test\aaa.txt) do (
set FPATH=%%~dpI
set FNAME=%%~nxI
goto echo
)

:echo
echo Filepath is %FPATH%
echo Filename is %FNAME%
echo.
echo.
pause
From that, you can use %FPATH% and %FNAME% wherever you want in your code.Thanks a lot dude....thank u very much No PROBLEM! Glad to see that your question is ANSWERED.