include
#include
using namespace std;
int main()
{
unsigned long int birthmonth,birthyear,birthhour;
unsigned long int currentmonth,currentyear,currenthour;
unsigned long int agey,agem,aget,ages;
double agemils,agemics,agens,ageps,agefs;
char ans;
top:
cout<<"\n\n\t\t\t WELCOME TO AGE CALCULATOR\n\n";
cout<<"Enter Your BIRTH Year(Eg:1989):";
cin>>birthyear;
cout<<"\n\nEnter Your Birth Month(Eg:7):";
cin>>birthmonth;
cout<<"\n\nEnter your birth hour(eg:3):";
cin>>birthhour;
cout<<"\nEnter The Current Year(Eg:2010):";
cin>>currentyear;
cout<<"\nEnter The Current Month(Eg:7):";
cin>>currentmonth;

cout<<"\nEnter The Current Hour(Eg:6):";
cin>>currenthour;
agey=currentyear-birthyear;
if(currentmonth>birthmonth)
{
agem=((currentyear-birthyear)*12)+(curre…
}
else
{
agem=((currentyear-birthyear-1)*12)+(cur…
}

aget=agem*30*24;
ages=aget*60;
agemils=aget*60*1000;
agemics=agemils*1000;
agens=agemics*1000;
ageps=agens*1000;
agefs=ageps*1000;
cout<<"\n\nYour Age in years= "<cout<<"\n\nYour Age in Milliseconds= "<cout<<"\n\nYour Age in Picoseconds= "<cout << "\n Do you want to TRY Again? (Y/N)" <<

endl;

cout << "Option: ";

char runAgain;

cin >> runAgain;



if (!(runAgain == 'N' || runAgain == 'n'))
{
goto top;
}

if (!(runAgain == 'Y' || runAgain == 'Y'))

{
cout<<"Thanks For Trying";
}


getch();
}


Question:
I am doing a c++ project to check age from years,months.....femtoseconds. The problem is i am not getting the output required. i am getting correct
results upto agemils(age in milli seconds) then i get something e+xxxxx(x= number) like that. so i tried cout.precision() statement. then i dont get e+(exponential form(i guess!!)
but still i am not getting correct results. for conversion of milli to micro,micro to nano,nano to pico,pico to femto i just need 3 zeroes extra at every successive outputs keeping numbers same. but i am getting different numbers . this is quite strange i changed all data types. please help me with this problem soon.


Point out my mistakes and give new ideas (if any)

I am beginner to c++ so please explain me in detail

sorry for such a long questionQuote

then i get something e+xxxxx(x= number)

aget=agem*30*24;
ages=aget*60;
agemils=aget*60*1000;
agemics=agemils*1000;
agens=agemics*1000;
ageps=agens*1000;
agefs=ageps*1000;

Looking at this conversion formula I think there is a typo too

Yes its the correct output however if you want a long long number vs scientific notation, you could take a number like 284,000,000,000,000,000,000 and divide it to use the 284 and concatonate your 0's on the tail of the output.

such as

Code: [Select]int After_Division;

cout<<After_Division<<",000,000,000,000,000,000\n";to get 284,000,000,000,000,000,000

You can use your existing output from ages below and include that in every cout<<ages then for agemils have cout<<ages<<"000\n"; and have cout<<ages<<"000000\n"; for agemics, then cout<<ages<<"000000000\n"; for agens and then cout<<"000000000000\n"; for ageps outputs and stack your 0's on the end.

There's also another issue with goto: it's not usually implemented well (or at all) in other programming languages, decreasing portability.

An example is TI-BASIC (Used on the TI-83/84 series of calculators), where if statements and loops used a stack mechanism to remember the beginning of the statement until it was ended. Goto could be used to jump out of one of these structures, possibly starting another loop. Eventually, an ERR: MEMORY would come up because of how much memory was used by the stack mechanism and how many loops had piled up unended. Needless to say, that was a pretty serious problem.

BC can you explain

double someval=40E120;
cout<<fixed<<someval<<endl;

I dont see any scale to this concationation of an INT and DOUBLE for each ms, ns, ps etc?

and the calculation is partially redundant to the prior formula above it.

It looks much cleaner as below even though you will end up with same output.