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Solve `sin^(-1) [sin((2x^(2) + 4)/(1 + x^(2)))] lt pi -3` |
Answer» `sin^(-1)[sin((2x^(2) + 4)/(1 + x^(2)))] lt pi - 3` Now, `(2x^(2) + 4)/(1 + x^(2)) = (2x^(2) + 2 + 2)/(1 + x^(2)) = 2 + (2)/(1 + x^(2))` So, `2+(2)/(1 + x^(2)) in (2, 4]` Therefore, Eq. (i) reduces to `pi-(2x^(2) + 4)/(1 + x^(2)) lt pi - 3` or `(2x^(2) + 4)/(1 + x^(2)) gt 3` or `2x^(2) + 4 gt 3 + 3x^(2)` or `x^(2) - 1 lt 0` or `-1 lt x lt1` |
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