solve `sin^(-1) (sin 5) gt x^(2) - 4x`

1.	solve `sin^(-1) (sin 5) gt x^(2) - 4x`
Answer» Correct Answer - `2 0 sqrt(9 - 2pi) lt x lt 2 + sqrt(9 - 2pi)` We have `sin^(-1) (sin 5) gt x^(2) - 4x` Since, `(3pi)/(2) lt 5 lt (5pi)/(2)` `:. Sin^(-1) (sin 5) = 5 - 2pi` `rArr 5 - 2pi gt x^(2) - 4x` `rArr x^(2) - 4x + 4 lt 9 - 2pi` `rArr (x - 2)^(2) lt 9 - 2pi` rArr -sqrt(9 - 2pi) lt x x - 2 lt sqrt(9 - 2pi)` `rArr 2- sqrt(9 - 2 pi) lt x lt 2 + sqrt(9 - 2 pi)`

Discussion

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