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Solve `sqrt(x-2)(x^2-4x-5)=0.` |
Answer» Correct Answer - `x = 2 or 5` Given equation is solvable for x`in [2,infty)`. Now `sqrt(x - 2)(x^(2) - 4x - 5) = 0` or `sqrt(x - 2)(x - 5)(x - 1) = 0` lt `rArr x = 2 or 5 (x ne -1, as x in [2, infty)` |
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