1.

Solve the differential equation \(\frac{dy}{dx}\) = y sin 2x, given that y(0) = 1.

Answer»

We have,

\(\frac{dy}{dx}\) = y sin 2x

⇒ \(\frac{dy}{y}\) = y sin2x

⇒ log y = - \(\frac{cos2x}2\) + c

For y =1, x = 0, we have,

c = \(\frac{1}{2}\)

⇒ log y = \(\frac{1}{2}\)(1 - cos2x)

⇒ log y = sin2x

Thus, 

The particular solution is:

y = esin2x



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