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Solve the equation `5^(x^(2)+3x+2)=1` |
Answer» This equation is equivalent to `x^(2)+3x+2=0` `implies(x+1)(x+2)=0` `:.x_(1)=-1,x_(2)=-2` consequently, this equation has two roots `x_(1)=-1` and `x_(2)=-2`. |
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