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Solve the equation `log_(((2+x)/10))7=log_((2/(x+1)))7`. |
Answer» The given equation is equivalent to `{(2/(x+1)gt0),(2/(x+1)!=1),((2+x)/10=2/(x+1)):}implies{(x+1gt0),(x!=1),(x=-6,3):}` `:.x_(1)=3` is root of the original equation. |
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