1.

Solve the equation `log_(3)(5+4log_(3)(x-1))=2`

Answer» We have `log_(3)(5+4log_(3)(x-1))=2`
is equivalent ot the equation(here base `!=1,gt0`)
`:.5+4log_(3)(x-1)=3^(2)`
`implieslog_(3)(x-1)=1impliesx-1=3^(1)`
`:.x=4`
Hence `x_(1)=4` is the solution of the original equation.


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