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Solve the equation `log_(3)(5+4log_(3)(x-1))=2` |
Answer» We have `log_(3)(5+4log_(3)(x-1))=2` is equivalent ot the equation(here base `!=1,gt0`) `:.5+4log_(3)(x-1)=3^(2)` `implieslog_(3)(x-1)=1impliesx-1=3^(1)` `:.x=4` Hence `x_(1)=4` is the solution of the original equation. |
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