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Solve the equation `log_((log_(5)x))5=2` |
Answer» We have `log_((log_(5)x))5=2` Base of logarithm `gt0` and `!=1` `:.log_(4)xgt0` and `log_(5)x!=1` `impliesxgt1` and `x!=5` `:.` The original equation is equivalent to `log_(5)x=5^(1//2)=sqrt(5)` ltrgt `:.x_(1)=5^(sqrt(5))` Here `5^(sqrt(5))` is the only root of the original equation. |
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