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Solve the following equation by factorizationmethod: `3x^2+7i x+6=0` |
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Answer» Correct Answer - `{(2)/(3)i, -3i}` a = 3, b = 7i and c = 6. `therefore" "(b^(2)-4ac)={(7i)^(2)-4xx3xx6}=(-49-72)=(-121)lt 0`. So, the given equation has complex roots, given by `(-b+-sqrt(b^(2)-4ac))/(2a)=(-7i+-sqrt(-121))/(2xx3)=(-7i+-11i)/(6)`. Solution set `={(-7i+11i)/(6),(-7i-11i)/(6)}={(2)/(3)i,-3i}` |
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