1.

Solve the following inequalities for real x. \(\frac{2x-3}{4}\) − 3< \(\frac{x-4}{3}\) −2, x ∈ R.

Answer»

We have, 

\(\frac{2x−3}{4}\)−3 < \(\frac{x−4}{3}\)−2,

\(\frac{2x−9}{4}\) < \(\frac{x−10}{3}\)

\(\frac{x}{2}\)\(\frac{x}{3}\) < \(\frac{−10}{3}\) + \(\frac{9}{4}\)

[Transposing \(\frac{x}{2}\)to LHS and \(\frac{9}{4}\) to RHS]

\(\frac{x}{6}\) < \(\frac{13}{12}\)

⟹ x < \(\frac{13}{2}\)

∴ x ∈ (−∞, \(\frac{13}{2}\))



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